(1/x^6)-(9/x^3)+8=0

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Solution for (1/x^6)-(9/x^3)+8=0 equation:


D( x )

x^3 = 0

x^6 = 0

x^3 = 0

x^3 = 0

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x^6 = 0

x^6 = 0

1*x^6 = 0 // : 1

x^6 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/(x^6)-(9/(x^3))+8 = 0

1/(x^6)-9*x^-3+8 = 0

x^-6-9*x^-3+8 = 0

t_1 = x^-3

1*t_1^2-9*t_1^1+8 = 0

t_1^2-9*t_1+8 = 0

DELTA = (-9)^2-(1*4*8)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)+9)/(1*2) or t_1 = (9-49^(1/2))/(1*2)

t_1 = 8 or t_1 = 1

t_1 = 1

x^-3-1 = 0

1*x^-3 = 1 // : 1

x^-3 = 1

-3 < 0

1/(x^3) = 1 // * x^3

1 = 1*x^3 // : 1

1 = x^3

x^3 = 1 // ^ 1/3

x = 1

t_1 = 8

x^-3-8 = 0

1*x^-3 = 8 // : 1

x^-3 = 8

-3 < 0

1/(x^3) = 8 // * x^3

1 = 8*x^3 // : 8

1/8 = x^3

x^3 = 1/8 // ^ 1/3

x = 1/2

x in { 1, 1/2 }

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